# Properties of Trapezoids and Kites

Now that we’ve seen several types of
that are
parallelograms
, let’s learn about figures that do not have the properties
of parallelograms. Recall that parallelograms were quadrilaterals whose opposite
sides were parallel. In this section, we will look at quadrilaterals whose opposite
sides may intersect at some point. The two types of quadrilaterals we will study
are called trapezoids and kites. Let’s begin our study by learning
some properties of trapezoids.

## Trapezoids

Definition: A trapezoid is a quadrilateral with exactly one pair of parallel
sides.

Since a trapezoid must have exactly one pair of parallel sides, we will need to
prove that one pair of opposite sides is parallel and that the other is not in our

two-column geometric proofs
. If we forget to prove that one pair of opposite
sides is not parallel, we do not eliminate the possibility that the quadrilateral
is a parallelogram. Therefore, that step will be absolutely necessary when we work
on different exercises involving trapezoids.

Before we dive right into our study of trapezoids, it will be necessary to learn
the names of different parts of these quadrilaterals in order to be specific about
its sides and angles. All trapezoids have two main parts: bases and legs.
The opposite sides of a trapezoid that are parallel to each other are called bases.
The remaining sides of the trapezoid, which intersect at some point if extended,
are called the legs of the trapezoid. The top and bottom sides of the trapezoid run parallel to each other, so they are
the trapezoid’s bases. The other sides of the trapezoid will intersect if extended,
so they are the trapezoid’s legs.

The segment that connects the midpoints of the legs of a trapezoid is called the
midsegment. This segment’s length is always equal to one-half the sum of
the trapezoid’s bases, or Consider trapezoid ABCD shown below. The midsegment, EF, which is shown in red, has a length of The measurement of the midsegment is only dependent on the length of the trapezoid’s
bases. However, there is an important characteristic that some trapezoids have that
is solely reliant on its legs. Let’s look at these trapezoids now.

## Isosceles Trapezoids

Definition: An isosceles trapezoid is a trapezoid whose legs are congruent.

By definition, as long as a quadrilateral has exactly one pair of parallel lines,
then the quadrilateral is a trapezoid. The definition of an isosceles trapezoid
adds another specification: the legs of the trapezoid have to be congruent. ABCD is not an isosceles trapezoid because AD and BC are not congruent. Because EH
and FG are congruent, trapezoid EFGH is an isosceles trapezoid.

There are several theorems we can use to help us prove that a trapezoid is isosceles.
These properties are listed below.

(1) A trapezoid is isosceles if and only if the base angles are congruent.

(2) A trapezoid is isosceles if and only if the diagonals are congruent.

(3) If a trapezoid is isosceles, then its opposite angles are supplementary.

## Kites

Definition: A kite is a quadrilateral with two distinct pairs of adjacent
sides that are congruent.

Recall that parallelograms also had pairs of congruent sides. However, their congruent
sides were always opposite sides. Kites have two pairs of congruent sides that meet
at two different points. Let’s look at the illustration below to help us see what
a kite looks like. Segment AB is adjacent and congruent to segment BC. Segments AD and CD are also

Kites have a couple of properties that will help us identify them from other quadrilaterals.

(1) The diagonals of a kite meet at a right angle.

(2) Kites have exactly one pair of opposite angles that are congruent.

These two properties are illustrated in the diagram below. Notice that a right angle is formed at the intersection of the diagonals, which is
at point N. Also, we see that ?K??M. This is our only pair of congruent angles because
?J and ?L have different measures.

Let’s practice doing some problems that require the use of the properties of trapezoids
and kites we’ve just learned about.

### Exercise 1

Find the value of x in the trapezoid below. Because we have been given the lengths of the bases of the trapezoid, we can figure
out what the length of the midsegment should be. Let’s use the formula we have been
given for the midsegment to figure it out. (Remember, it is one-half the sum of
the bases.)    So, now that we know that the midsegment’s length is 24, we can go
ahead and set 24 equal to 5x-1. The variable is solvable
now:   ### Exercise 2

Find the value of y in the isosceles trapezoid below. In the figure, we have only been given the measure of one angle, so we must be able
an isosceles trapezoid, we know that the base angles are congruent. This means that
?A also has a measure of 64°.

Now, let’s figure out what the sum of ?A and ?P is:   Together they have a total of 128°. Recall by the Polygon Interior
Angle Sum Theorem
that a quadrilateral’s interior angles must be 360°.
So, let’s try to use this in a way that will help us determine the measure of
?R
. First, let’s sum up all the angles and set it equal to 360°.   Now, we see that the sum of ?T and ?R is 232°.
Because segment TR is the other base of trapezoid TRAP,
we know that the angles at points T and R must be congruent
to each other. Thus, if we define the measures of ?T and ?R
by variable x, we have   This value means that the measure of ?T and ?R is
116°
. Finally, we can set 116 equal to the expression shown in ?R
to determine the value of y. We have     So, we get x=9.

While the method above was an in-depth way to solve the exercise, we could have
also just used the property that opposite angles of isosceles trapezoids are supplementary.
Solving in this way is much quicker, as we only have to find what the supplement
of a 64° angle is. We get   Once we get to this point in our problem, we just set 116 equal to
4(3y+2) and solve as we did before.

### Exercise 3  After reading the problem, we see that we have been given a limited amount of information
and want to conclude that quadrilateral DEFG is a kite. Notice that
EF and GF are congruent, so if we can find a way to
prove that DE and DG are congruent, it would give us
two distinct pairs of adjacent sides that are congruent, which is the definition
of a kite.

We have also been given that ?EFD and ?GFD are congruent.
We learned several triangle congruence theorems in the past that might be applicable
in this situation if we can just find another side or angle that are congruent.

Since segment DF makes up a side of ?DEF and ?DGF,
we can use the reflexive property to say that it is congruent to itself.
Thus, we have two congruent triangles by the SAS Postulate.

Next, we can say that segments DE and DG are congruent
because corresponding parts of congruent triangles are congruent. Our new illustration
is shown below. We conclude that DEFG is a kite because it has two distinct pairs
of adjacent sides that are congruent. The two-column geometric proof for this exercise
is shown below. Scroll to Top